10p^2+8p=8

Solution for 10p^2+8p=8 equation:

10p^2+8p=8

We move all terms to the left:

10p^2+8p-(8)=0

a = 10; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·10·(-8)
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{6}}{2*10}=\frac{-8-8\sqrt{6}}{20}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{6}}{2*10}=\frac{-8+8\sqrt{6}}{20}
$